What amount of bromine will be required to convert 6 g of phenol into 2,4,6-tribromophenol?

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Shift 23/05/2023 3:30 PM - 6:30 PM

30.63 g

40.64 g

20. 38 g

15.63 g

Correct Answer

30.63 g

1: 30.63 g.

C6H5OH+3Br2→C6H2Br3OH+3HBr

The molecular weight of phenol = 94 g

molecular weight of 3Br2 = 3 x 160 = 480g

94g of phenol requires 480g of Br2

6g of phenol requires = 480/94 x 6 =30.63g

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