The product obtained from the catalytic reduction of propanal (CH3CH2CHO) is Propan-1-ol (CH3CH2CH2OH). So, the correct option is:

The statement is correct. The catalytic reduction of propanal (CH3CH2CHO) with a suitable reducing agent, such as hydrogen gas (H2), in the presence of a catalyst like a metal catalyst (e.g., palladium or nickel) results in the formation of propan-1-ol (CH3CH2CH2OH).

Here's the balanced chemical equation for the catalytic reduction of propanal to form propan-1-ol:

CH3CH2CHO + H2 (catalytic reduction) → CH3CH2CH2OH

In this reaction:

1. Propanal (CH3CH2CHO) is an aldehyde with a carbonyl group (C=O) at the end of the carbon chain.
2. Hydrogen gas (H2) serves as the reducing agent.
3. A suitable catalyst, often a metal catalyst like palladium (Pd) or nickel (Ni), is used to facilitate the reduction process.

The reduction of the carbonyl group (C=O) in propanal involves the addition of hydrogen (H2) to the carbon atom in the carbonyl group, reducing it to a hydroxyl group (-OH). This leads to the formation of propan-1-ol, also known as 1-propanol, which is a primary alcohol.

The reaction results in the conversion of the carbonyl group (C=O) in propanal to a hydroxyl group (OH), and the product, propan-1-ol, has the -OH group at the first carbon (carbon-1) in the propane chain, which is why it is named propan-1-ol.

So, the correct option is indeed that the product obtained from the catalytic reduction of propanal is propan-1-ol (CH3CH2CH2OH).

1. Propan-1-ol