If we plot graph for first order reaction involving reactant R, then it will be a straight line if plotted for :
This question was previously asked in
Shift 23/05/2023 3:30 PM - 6:30 PM
A
[R] /[R] against time, t
B
[R]. against time, t
C
log [R]/[R]. against time, t
D
[R] against time, t
Correct Answer
log [R]/[R]. against time, t
Detailed Explanation
For a first-order reaction, the integrated rate law is given by:
ln[R]=−KT+ln[R0]
This equation represents a straight line when ]ln[R]/[R]. is plotted against time t
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