The capacitance of a capacitor is 4uF and it's potential is 100 V. The energy released on discharging it fully will be
This question was previously asked in
Shift 23/05/2023 3:30 PM - 6:30 PM
A
0.02 J
B
0.04 J
C
0.025 J
D
0.05 J
Correct Answer
0.02 J
Detailed Explanation
Potential energy lost during discharge of the capacitor is U=(CV^2)/2
Given C=4μF,V=100V
U=(4x10^-6 x 10^4)/2
U=0.02J.
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